Calculating Time of Flight for a Golf Ball

AI Thread Summary
To calculate the time of flight for a golf ball launched at an initial velocity of 40 m/s at a 35-degree angle, the vertical component of the velocity must be determined. The vertical velocity can be calculated using the formula Vi_y = Vi * sin(θ). The time to reach the maximum height is found by setting the final vertical velocity to zero and using the equation t = Vi_y / g, where g is the acceleration due to gravity (approximately 9.81 m/s²). The total time of flight is twice this value, as the ascent and descent times are equal. This approach provides a clear method to solve for the time of flight.
shobb
Messages
1
Reaction score
0

Homework Statement


What is the time of flight of a golf ball? The Vi=40 m/s, the angle is 35 degrees, and the mass is .046kg.

Homework Equations



I'm assuming I need to use <br /> v = v_0 + a t<br /> but I don't know the final velocity or how to get it.

The Attempt at a Solution


I'm totally stuck
 
Physics news on Phys.org
shobb said:

Homework Statement


What is the time of flight of a golf ball? The Vi=40 m/s, the angle is 35 degrees, and the mass is .046kg.

Homework Equations



I'm assuming I need to use <br /> v = v_0 + a t<br /> but I don't know the final velocity or how to get it.

The Attempt at a Solution


I'm totally stuck

Consider the vertical direction. How long does it take to reach its maximum point (where vertical velocity is 0)? How long does it take to come back down again?
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top