Calculating Torpedo Angle & Travel Time to Hit Carrier 5 Miles N

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SUMMARY

The discussion focuses on calculating the angle and travel time for a submarine's torpedo to hit a carrier located 5 miles north while the carrier is moving east at 3 miles per hour. The torpedo travels at a speed of 40 knots. By applying the Pythagorean theorem, the problem can be formulated into a quadratic equation to determine the necessary angle and distance for the torpedo's trajectory. The travel time can be derived from the calculated distance and the torpedo's speed.

PREREQUISITES
  • Understanding of basic trigonometry and angles
  • Familiarity with the Pythagorean theorem
  • Knowledge of speed and distance calculations
  • Ability to solve quadratic equations
NEXT STEPS
  • Research how to apply the Pythagorean theorem in projectile motion
  • Learn about torpedo ballistics and travel time calculations
  • Study the conversion between knots and miles per hour
  • Explore quadratic equation solving techniques
USEFUL FOR

Students studying physics or mathematics, naval strategists, and anyone interested in naval warfare tactics and projectile motion calculations.

rastakitty
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need help.. carrier 5 miles N of sub traveling E @ 3mins/hr. sub has torpedoe travel @ 40 knots. what is the angle and distance travel of torpedoe to hit carrier, what is travel time . with respect to original sighting
 
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pythagorean theorem gives quadratic equation in lengths. then diff lengths wrt t.
 
Obviously a homework problem, obviously no work shown.
 

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