Calculating Torque on an Apple: Fx, Fy, Fz

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SUMMARY

The discussion focuses on calculating torque on an apple located at coordinates (-3.0, 0, 7.0) m due to various force components, specifically Fx and Fz. The torque is calculated using the formula T = r × F, where r is the position vector and F is the force vector. For Fx = 2.0 N, the torque about the origin is -6 N*m, derived from the equation T = -3 * 2.0 N. The participants clarify that torque is dependent on the perpendicular distance from the axis of rotation and the force applied.

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What is the magnitude of the torque about the origin of an apple at coordinates (-3.0, 0, 7.0) m due to force F whose only component is Fx = 2.0 N?
What is the y-component of this torque?
What is the magnitude of the torque if the force is Fx = - 2.0 N?
What is the y-component of this torque?
What is the magnitude of the torque if the force is Fz = 2.0 N?
What is the y-component of this torque?

t=Ia or is there another equation?


t=-3*2.0 N= -6 N*m
I did N*m for the other ones but still getting the answer wrong.
 
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If (-3.0, 0, 7.0) is a point in 3D space (x,y,z) then...

t=-3*2.0

is that T = x * F ?

I believe that should be T = z * F

Draw it.
 

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