Calculating Total Electric Charge in a 50kg Sample of Water

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SUMMARY

The total electric charge of all electrons in a 50kg sample of water can be calculated using the atomic numbers and molar mass of its constituent elements, hydrogen and oxygen. Hydrogen has an atomic number of 1 and oxygen has an atomic number of 8. The molar mass of water (H2O) is 18 grams/mol, and Avogadro's number (N_A) is 6.02 x 1023 mol-1. By determining the number of moles in 50kg of water and multiplying by the total number of electrons, one can derive the total electric charge.

PREREQUISITES
  • Understanding of atomic structure and electron configuration
  • Familiarity with molar mass calculations
  • Knowledge of Avogadro's number (N_A)
  • Basic principles of electric charge
NEXT STEPS
  • Calculate the number of moles in 50kg of water using the molar mass of 18 grams/mol
  • Determine the total number of electrons in a water molecule (H2O)
  • Learn how to calculate total electric charge using the formula Q = n * e, where e is the charge of an electron
  • Explore the implications of electric charge in chemical reactions and molecular interactions
USEFUL FOR

Students studying chemistry, physics, or electrical engineering, as well as educators looking for practical examples of calculating electric charge in molecular compounds.

dtrain121
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Homework Statement


Find the total electric charge of all the electrons in a 50kg sample of water


Homework Equations


a conversion factor


The Attempt at a Solution


I need the atomic # and the atomic mass but it is water. If I had those two i could solve the problem. How do i get those two things?
 
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Water is H2O - two oxygen and two hydrogen atoms. You can look up their masses and charges on a periodic table or look up the elements in Wikipedia.
 
The atomic number of an element also tells you have many electrons it has.
The atomic number of Hydrogen is 1, and that of oxygen is 8.

The molar mass of water is 18 grams/mol.

There are [tex]N_A[/tex] molecules in one mol of substance.

[tex]N_A=6.02*10^{23} mol^{-1}[/tex]
 

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