Calculating Uncertainty, involving a logarithmic quantity

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The discussion focuses on calculating the uncertainty in absolute magnitude (M) using the equation M = m - 5 log10 (d/10). The variable μ is defined as μ = -5 log10 (d/10), leading to the uncertainty Δμ being expressed as Δμ = 5 * (Δd / d * ln(10)). The method for calculating the overall error in M incorporates both the uncertainties in m and μ, resulting in ΔM2 = [Δm2 + Δμ2]. The approach is validated as a good estimate for the overall error, emphasizing the importance of including ln(10) in the calculations. This method provides a reliable framework for assessing uncertainties in logarithmic quantities.
Rodger
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Essentially I'm asking if the uncertainty in μ = -5 log10 (d/10) is given by Δμ = 5 * ( Δd / d*ln(10) )


1. The problem, all variables and given/known data

I am to calculate the uncertainty in absolute magnitude (M), which is calculated using an equation involving logs.

The equation for M is: M = m - 5 log10 (d/10) where m and d have associated errors Δm and Δd.


The Attempt at a Solution



I introduce: μ = -5 log10 (d/10) such that M = m + μ

Then I calculate the error in μ whereby: Δμ = 5 * ( Δd / d*ln(10) )

I then calculate the error in M by:

ΔM2 = [ Δm2 + Δμ2 ]

Any comments on this would be greatly appreciated as I have 0 confidence in myself when it comes to calculating errors.
 
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Yes that method will give you a good estimate of the overall error.
 
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Yes, provided that ln10 is in the denominator.

Chet
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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