Calculating Uncertainty on (R^2 + z^2) ^3/2

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Can someone tell me how to claculate the uncretinty on

(R^2 + z^2) ^3/2
 
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Assuming R and z are independent variables, you do it the same way you calculate the uncertainty in any multi variable function:

\Delta f(R,z) \approx \left| \frac{\partial f}{\partial R} \right| \Delta R+\left| \frac{\partial f}{\partial z} \right| \Delta z
 
Isn't that just for (z^2 + R^2)?
 
Also if you have a cos/sin function in an equation(multiplying) how would you do it for cos/sin?

is it just for cos x = sinxdx/cosx and cosxdx/sinx for sin x?
 
Why would it apply to one multi variable function, but not the others?
 
So would I just take the uncertainty on z^2 + R^2, then multiply in by 3/2 and squareroot z^2 + R^2?
 
Gogsey said:
Also if you have a cos/sin function in an equation(multiplying) how would you do it for cos/sin?

is it just for cos x = sinxdx/cosx and cosxdx/sinx for sin x?

Do you know how to take derivatives? And what happened to the absolute value brackets?...Errors are never negative.

\left| \frac{\partial}{\partial x} (\cos x) \right|\Delta x= |-\sin(x)|\Delta x=|\sin(x)|\Delta x \neq \frac{\sin x}{\cos x}dx

Also, \Delta x is the uncertainty in x, not the differential 'dx'.
 
Gogsey said:
So would I just take the uncertainty on z^2 + R^2, then multiply in by 3/2 and squareroot z^2 + R^2?

No, you would compute the absolute value of the partial derivative of (R^2+z^2)^{3/2} with respect to R and multiply it by the uncertainty in R; then do the same with respect to z, and then add them together...
 
Ok that's for cos x, but I need (unceratinty in cosx)/cosx. The relative over the value.
 
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