Calculating Volume of a Cone: Need Help?

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    Cone Volume
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Homework Help Overview

The discussion revolves around calculating the volume of a cone, with a specific focus on identifying the correct formula to use. The original poster expresses uncertainty about the appropriate equation for a cone, particularly in relation to the dimensions provided.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the validity of using the standard cone volume formula, questioning whether it applies to a cone described as "abnormal." There is also a focus on ensuring the correct units for volume are being used, with discussions about the implications of squared versus cubed units.

Discussion Status

Participants have engaged in clarifying the formula for the volume of a cone and have confirmed that the standard equation can be applied. There appears to be a productive exchange regarding unit consistency and the application of the formula, though no final consensus on the specific dimensions or calculations has been reached.

Contextual Notes

The original poster's problem includes an attachment that may contain additional information relevant to the cone's dimensions, which is not explicitly detailed in the discussion. There is an indication of a misunderstanding regarding the height of the cone in earlier posts.

golb0016
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Homework Statement


Find the volume, see attachment


Homework Equations


I can't find the proper equation for this cone.


The Attempt at a Solution


he triangle is a 3, 4, 5 triangle. Is the typical cone equation of 1/3*PI*r^2*h used or a different equation?
 

Attachments

  • cone.gif
    cone.gif
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Look at the units your equation would produce. If you used your equation you would get a unit that is squared implying a surface area such as meters squared (m^2). For a volume you need a unit that is cubed. So your equation is incorrect.

Think of what you need to get the correct unit of volume.

Thanks
Matt
 
The units would be m^3 (r*r*h)
 
You got it.

Now substitute the (r*r)*h into your equation from post 1 and you should get the correct answer.

Sorry, I didn't catch the h in your first post. Looks you had it right all along.

Thanks
Matt
 
So the regular cone equation can be used even though the cone is abnormal?
 
Yes it can be.

Thanks
Matt
 

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