Calculating Volume of Revolution: Bounded Figure Rotated about y = -1

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SUMMARY

The volume of the figure bounded by the equations y = 2x - x^2, y = 2x, and x = 2, when rotated about the line y = -1, is calculated using the integral V = π ∫₀² ((2x + 1)² - (2x - x² + 1)²) dx. This integral correctly represents the volume of revolution for the specified region. The discussion confirms the accuracy of the integral provided for this calculation.

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ChaoticLlama
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What is the volume of the figure bounded by y = 2x - x^2, y = 2x, x = 2, and rotated about the line y = -1.

Is this the correct integral?

[tex]\[<br /> V = \pi \int_0^2 {((2x + 1)^2 - (2x - x^2 + 1)^2 } )dx<br /> \][/tex]

Thank you for your time.
 
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Yes, your answer is correct.
 

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