kostoglotov
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Homework Statement
imgur link: https://i.imgur.com/9jozS67.png
Homework Equations
The Attempt at a Solution
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Shouldn't I use V_{rms} = \sqrt{\frac{1}{T}\int_T v^2 dt}?
Which would be
\sqrt{\frac{100}{2\pi}\int_0^{2\pi/100}(20+60cos(100t))^2dt}
This equals \approx 79.88 V
The answer is given as \approx 46.9V and the solution manual shows the following working
\sqrt{20^2 + \frac{60^2}{2}}
Why do they apply that solution and not the one I used?