The discussion centers on the calculation of RMS voltage for a sine wave with a peak-to-peak voltage of 1V. The formula for RMS voltage without an offset is confirmed as Vrms = 1/(√2)Vpeak. The participant initially misinterpreted the problem by considering an offset, which typically refers to a DC component added to the sine wave. Ultimately, it was clarified that the sine wave in question does not have an offset, leading to the correct interpretation of the RMS voltage calculation.
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Hi Ardec, Welcome to Physics Forums.Ardec said:Homework Statement
The rms voltage for a sine wave with zero offset is given by Vrms= 1/(√2)Vpeak. Calculate the rms voltage for a sine wave with a peak-to-peak voltage of 1V.
Homework Equations
Vpeak-to-peak=2Vpeak
The Attempt at a Solution
This may be a really easy question with an answer of (√2)/4 but i wasn't sure if you could use the equation Vpeak-to-peak=2Vpeak with an offset in the sine wave.
I miss read the question and correct myself the second after i posted this, there is no offset, and i didn't see a way to delete the thread. Thanks anyways for the answergneill said:Hi Ardec, Welcome to Physics Forums.
Your answer will depend upon what you mean by an "offset". Usually an offset means that there is a DC component added to the signal, so for example a sinewave riding on a DC value. This has the effect of shifting the sinewave up or down from the 0V level. But taking the problem as stated you simply have a sinewave with a peak voltage of 1/2 V, no offset. So can you explain what you mean by offset?