A power station is supplied with water from a reservoir. A pipeline connects the reservoir to the turbine hall(adsbygoogle = window.adsbygoogle || []).push({});

The flow of water through the pipeline is controlled by a valve which is located exactly 500 metres below the surface of the water in the reservoir. The pipeline is 0.30 m in diameter.

Calculate the static pressure at the lower end of the pipeline when the valve is in the closed position

relivant equation

bernouliis equation

P + 1/2 rho v^2 + pgh = constant

my attempt so far -

for the surface of the reservior

P1 - atmospheric pressure 1.00x10^5

rho1 = density of water 1.00x10^3

g = 9.81

h1 = 0

v1 = 0 (water is not moving)

for the bottom of the pipe

p2 - unknown

rho 2 = density of water 1.00x10^3

g = 9.81

h2 = 500

v2 - 0 (water not moving)

rearrange for p2

p2 = 1/2 Rho (V1-V2)g(h1-h2)-P1

this gives

1/2*1.00x10^3+1.00x10^3*9.81*(0-500)-1.00x10^5

so p2 = 4904500

or 4.9x10^6

can someone let me know if i went wrong anywhere as this doesnt look correct? i dont think the diamter of the pipe is important for this part of the equation,

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# Homework Help: Calculating water pressure from bernouliis equation

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