Calculating water pressure in a horizontal pipe

[Pushoam]

Homework Statement

Homework Equations

The Attempt at a Solution

Calculating water pressure using in a horizontal pipe

Applying Bernoulli principle,

$p_a + \frac 1 2 \rho gh_a + \frac 1 2 \rho v_a^2 = p_b + \frac 1 2 \rho gh_b + \frac 1 2 \rho v_b^2$

$h_a = h_b, v_b = \frac { A_a v_a}{A_b}$

Substituting the values gives, $p_a = 3 * 10^5 ~ N\m^2$ .

Is this correct?

 

[TSny]

$p_a + \frac 1 2 \rho gh_a + \frac 1 2 \rho v_a^2 = p_b + \frac 1 2 \rho gh_b + \frac 1 2 \rho v_b^2$

Your $\rho g h$ terms aren't written correctly. But this didn't affect your answer, which looks correct to m.

 

[Pushoam]

Your $\rho g h$ terms aren't written correctly. But this didn't affect your answer, which looks correct to m.

$\rho g h$ terms correspond to potential energies, the factor ½ should not be there. Right?

 

[TSny]

$\rho g h$ terms correspond to potential energies, the factor ½ should not be there. Right?

Right.

 

[Pushoam]

Thanks.