Calculating Wavelengths in de Broglie's Standing Wave Condition

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The discussion revolves around calculating the number of internal wavelengths in the fourth excited state of Be3+ using de Broglie's standing wave condition. Participants clarify that the integral number of wavelengths fitting into the Bohr orbit is determined by the principal quantum number, n, which is 5 for the fourth excited state. There is some confusion regarding the relevance of the charge and circumference, but it is concluded that these details are not necessary for answering the question. The main takeaway is that the problem is simpler than initially perceived, focusing on the number of wavelengths rather than their specific values. Overall, the conclusion is that there are 5 internal wavelengths in this state.
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Homework Statement



de Broglies standing wave condition demands that an inegral number of wavelengths fit into the circumference of the Bohr orbit. How many "interal wavelengths" are there in the fourth exited state of Be3+?

Homework Equations



n lambda = 2 pi r

The Attempt at a Solution



i tried to solve using the equation above but was confused on lambda and r, both unknowns.

n = 5 because of fourth excited state i think
not sure what use the charge is in this problem...
 
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powerof1004 said:

Homework Statement



de Broglies standing wave condition demands that an inegral number of wavelengths fit into the circumference of the Bohr orbit. How many "interal wavelengths" are there in the fourth exited state of Be3+?

Homework Equations



n lambda = 2 pi r

The Attempt at a Solution



i tried to solve using the equation above but was confused on lambda and r, both unknowns.

n = 5 because of fourth excited state i think
not sure what use the charge is in this problem...

It seems to me the question is asking for the number of wavelengths, not a value/size of each wavelength. You had answered that. Perhaps I misread, or there was more to the question than you wrote ??
 
Yeah, I think you just answered your own question. As you said, there are 5 internal wave-lengths.
 
SpecialKM said:
Yeah, I think you just answered your own question. As you said, there are 5 internal wave-lengths.

really??
but i just used one piece of info and totally disregarded the rest and didnt use any formulas...
 
powerof1004 said:
really??
but i just used one piece of info and totally disregarded the rest and didnt use any formulas...

As I said, the [part of the] question you posted did not include any information which you feel you have "totally disregarded" ?

EDIT: And don't get hung up on always wanting to use a formula.
 
I didnt use Be3+ or any of the information of the circumference. I just came to n=5 due to fourth excited state.
wouldn't that be disregarding the other pieces of information?
 
powerof1004 said:
I didnt use Be3+ or any of the information of the circumference. I just came to n=5 due to fourth excited state.
wouldn't that be disregarding the other pieces of information?

If the question had said:

"How many "interal wavelengths" are there in the fourth exited state"

people may be wondering "How many "fourth exited state of what?"

I think the use of Be3+ is just there because some atom had to be.
 
Wow than this was a much simpler problem than i thought it would be
Thanks Guys
 

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