Calculating whether the force of a flow rate is sufficient to move a disc

Click For Summary
SUMMARY

The discussion focuses on calculating whether the force from a water flow rate is sufficient to lift a 7.3 kg disc in a vertical 10-inch pipeline. The flow rate of 2250 gpm at 198 psi was converted to 0.142 m³/s, resulting in a force of 144.43 kg/s. The area of the pipe was calculated to be 0.05067 m². The key question is determining the dynamic pressure required to overcome the gravitational force on the disc, with a delta P range of 5 to 7 psi and a maximum pressure of 290 psig as per ASME Class 150 standards.

PREREQUISITES
  • Understanding of fluid dynamics principles
  • Knowledge of pressure calculations in fluid systems
  • Familiarity with unit conversions (gpm to m³/s)
  • Basic physics of forces and gravity
NEXT STEPS
  • Research how to calculate dynamic pressure in fluid flow
  • Learn about the implications of delta P in hydraulic systems
  • Study the ASME Class 150 piping standards
  • Explore methods for calculating flow rates and forces in vertical pipelines
USEFUL FOR

Engineers, physics students, and professionals involved in fluid mechanics and hydraulic systems will benefit from this discussion, particularly those working with pipeline design and flow rate calculations.

MVPhysics
Messages
2
Reaction score
0

Homework Statement



There is a vertical 10 inch pipeline with a disc hanging in it. The disc weighs 7.3 kg. There is a flow coming from the opposite direction (water with density 1017.17 kgm/m3) coming at 2250 gpm at 198 psi in the opposite direction (moving up through a pipe). Is there sufficient force to open the free hanging disc? What is the minimum flow rate (in gpm) needed to raise the disc? Delta P is 5 to 7 psi.

b. how about 1680 gpm at 122 psi ?

Homework Equations



None provided, but equations used below.


The Attempt at a Solution



First I calculated the Force of the disc which would be 7.3kg (9.81 m/s2) = 71.613 kg m/s2

The flow rate of 2250 gpm was converted to 0.142 m3/s

0.142 m3/s * 1017.17 kg/m3 = 144.43 kg/s

The area of the pipe is A=∏r2 , so 78.5398 in2 or 0.05067 m2

I am not sure what the next step would be in comparing a Force (exerted by the disc and gravity) to the Force exerted by a flow rate.
 
Last edited:
Physics news on Phys.org
What is the dynamic pressure of the flow? What should it be to open the disk?
 
The delta P is 5 to 7 psi. and the piping is ASME Class150, so the pressure would never exceed 290 psig in the pipe. The only effects on the disc is gravity.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
5
Views
4K
  • · Replies 15 ·
Replies
15
Views
7K
  • · Replies 1 ·
Replies
1
Views
5K
Replies
2
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 2 ·
Replies
2
Views
7K
  • · Replies 5 ·
Replies
5
Views
7K
Replies
1
Views
3K