Calculating Work & Final Velocity of a 70kg Mass

AI Thread Summary
The discussion revolves around calculating the total work done and the final velocity of a 70kg mass subjected to two forces in space. The total work done is calculated as 508.75 J, derived from the initial kinetic energy and the work done by the forces applied. The participants clarify that the correct formula to find the final velocity involves using the initial kinetic energy plus the net work done. There is a correction regarding the inclusion of initial kinetic energy in the work calculation, emphasizing the need to focus on the change in work. The final velocity can be determined by rearranging the kinetic energy equation with the calculated work.
magma_saber
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Homework Statement


A 70kg mass is in a space and moving at 2.5 m/s. You push it with 200N for 4 m. You then move to the front of the mass and push it backwards with 170N for 3 m.

What was the total work done?
What was the final velocity?


Homework Equations


W = rest energy + F1*r - F2*r


The Attempt at a Solution


rest energy = 1/2*70*(2.5)2 = 218.75
F1*r = 200*4 = 800
F2*r = 170*3 = 510
W = 218.75 + 800 - 510 = 508.75 J

How would i get the final velocity?
 
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magma_saber said:
How would i get the final velocity?

Initial KE + Work = Final KE

Initial ½mv² + W = Final ½mv²
 
so its 218.75 + 800 + 510?
 
magma_saber said:
so its 218.75 + 800 + 510?

Perhaps I should rephrase that since you want to plug in numbers literally without thinking about the signs:

Initial ½mv² + ΔW = Final ½mv²

Btw your initial calculation incorrectly includes the initial KE in the ΔW they asked you to find.
 
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