Calculating Work to Close a Valve in Hydrodynamics

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To calculate the work required to close a valve in hydrodynamics, one must consider the pressure exerted by the fluid and the area of the valve. In this scenario, with a pressure of 2 MPa and a square cross-section of 1 m², the force acting on the valve can be calculated using the formula F = P × A. The work done to close the valve is then determined by the equation W = F × d, where d is the distance the valve moves. Given the valve's thickness of 10 cm, the total work can be computed based on these parameters. Understanding these principles is crucial for solving similar problems in hydrodynamics.
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Hey!
Yesterday I was on the Czech Physics Olympiad. There were many examples. To one, however, I did not invent anything, because I don't learn Hydrodynamics to much.
I want to understand it better, so I want to ask you how you calculate it, please. I'm sorry, I did not give my progress here, but I have not it, because I do not know much about Hydrodynamics. I spent two hours thinking but I did not invent it.

So... example:

Liquefied gas flowing in a pipeline. You want to close the pipeline. To close the pipeline you must close a valve (move plate across pipeline).
- in a large reservoir, where pipeline is connected, the pressure is 2 MPa
- valve (plate) has a thickness 10 cm
- pipe has a square cross section with a side length 1 m
- liquefied gas has a density 480 kg/m3 and and flow 20 m3/s

What is the value of work to close the valve?

Thanks... And if you don't understand me, write, i will try to write it better.
 
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