Calculation about virtual image

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The discussion revolves around calculating virtual images in optics, emphasizing the importance of visual aids like diagrams. It highlights that virtual images appear on the same side of the lens as the object, necessitating a negative value for image distance in calculations. Participants suggest that creating a picture can clarify the concept and aid in understanding the problem. The need for a quick nudge indicates a request for guidance on the homework solution. Visual representation is deemed crucial for grasping the relationship between object and virtual image.
barryj
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Homework Statement


See my attached information

Homework Equations


On my attached solution

The Attempt at a Solution


see my attached sheet

Please see my attached write up.
I would appreciate a quick nudge as stated.
 

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barryj said:

Homework Statement


See my attached information

Homework Equations


On my attached solution

The Attempt at a Solution


see my attached sheet

Please see my attached write up.
I would appreciate a quick nudge as stated.
Make a picture. Note that the virtual image is on the same side of the lens as the object. And the image distance has to be taken negative, if it is virtual image.
 
Last edited:
Thank you. Yes, a picture really is the key here.
 

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