Calculation of Change in Magnetic Flux Linkage Across a Wire

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SUMMARY

The calculation of the induced electromotive force (e.m.f.) across a straight wire moving through a magnetic field is effectively addressed using the formula emf = Blv, where B is the magnetic flux density (0.10 T), l is the length of the wire (0.20 m), and v is the velocity of the wire (3.0 m/s). The induced e.m.f. is calculated as 0.06 V. While Faraday's law is traditionally applied to loops, in this case, the use of the Blv law is more appropriate due to the wire's motion through the magnetic field. The discussion highlights the importance of understanding the distinction between applying Faraday's law to loops versus straight conductors in motion.

PREREQUISITES
  • Understanding of Faraday's law of electromagnetic induction
  • Familiarity with the Lorentz force and its application in electromotive force calculations
  • Basic knowledge of magnetic flux and its components
  • Ability to perform calculations involving velocity, magnetic flux density, and length of conductors
NEXT STEPS
  • Study the application of Faraday's law in different geometries, particularly loops versus straight wires
  • Learn about the Lorentz force and its implications in electromagnetic theory
  • Explore practical applications of the Blv law in electrical engineering
  • Investigate the concept of magnetic flux and its calculation in various scenarios
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Students studying electromagnetism, electrical engineers, and educators looking to deepen their understanding of electromagnetic induction and its applications in real-world scenarios.

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Homework Statement


A straight wire of length 0.20m moves at a steady speed of 3.0m/s at right angles to a magnetic filed of flux density 0.10T. Use Faraday's law to determine the e.m.f. induced across the ends of a wire.

Homework Equations


E= Nd Φ/dt but N=1 so E= dΦ/dt

The Attempt at a Solution


The solution offered in the book:

Φ=BA
dΦ = BdA
dΦ/dt=B*dA/dt
dΦ/dt=0.10*Area moved by the length of the wire in 1 second (??)
dΦ/dt=0.10*3.0*0.20=0.06

E=0.06V

Now I understand that since the conductor is moving in a magnetic field, electrons experience a force and a charge separation occurs giving rise to an e.m.f. across the wire... By Faraday's law, this e.m.f. is equal (in this case) to dΦ/dt but here's the problem... I do not see how a wire cutting a uniform magnetic field experiences a change in magnetic flux. Its area is constant and magnetic flux density is constant so the magnetic flux felt by the wire Φ=BA is constant. The solution used the area covered by the wire which seems to me very irrelevant.

Thanks in advance.
 
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Faraday refers to a loop, not a piece of wire. Draw an imaginary rectangular loop behind the wire, with the other end of the loop not in the B field, to get the answer using Faraday. dA/dt is the rate of change of the area in the loop covered by the flux. It can be + or -.

Actually, using Faraday with moving media such as your wire is dangerous. Better to use the Blv law based on the Lorentz force q v x B:
emf = Blv, l = length of wire, v = velocity of wire. Forget about loops.
 
rude man said:
Faraday refers to a loop, not a piece of wire. Draw an imaginary rectangular loop behind the wire, with the other end of the loop not in the B field, to get the answer using Faraday. dA/dt is the rate of change of the area in the loop covered by the flux. It can be + or -.

Actually, using Faraday with moving media such as your wire is dangerous. Better to use the Blv law based on the Lorentz force q v x B:
emf = Blv, l = length of wire, v = velocity of wire. Forget about loops.
I understand. Thank you sir
 

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