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- Thread starter ttpp1124
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Comment: Your vector equation isn't an equation. An equation always has '=' in it.Homework Statement::Determine vector and parametric equations for the plane containing the point A(2, 3, -1) and parallel to the plane with equation (x, y, z) = (2, 1, -3) + s(5, 2, -1) + t(3, -2, 4).

Can someone confirm?

Relevant Equations::n/a

View attachment 260205

Can you check these for yourself? Does your plane contain the point A(2, 3, -1)? Since your plane is parallel to the given plane, it should contain the same two vectors as the given plane.

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Comment: Your vector equation isn't an equation. An equation always has '=' in it.

Can you check these for yourself? Does your plane contain the point A(2, 3, -1)? Since your plane is parallel to the given plane, it should contain the same two vectors as the given plane.

To obtain a plane parallel to P0 and passing through the point A(2,3,−1), all we need to do is add A as a vector (I dropped the coordinates for brevity) to all the points of P0. This gives us the plane

(𝑥,𝑦,𝑧)=𝐴+𝑠(5,2,−1)+𝑡(3,−2,4)

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Yes,, I understand how you got the equation, but I was responding to your request for someone to verify that your work was correct. Here's what I said before:To obtain a plane parallel to P0 and passing through the point A(2,3,−1), all we need to do is add A as a vector (I dropped the coordinates for brevity) to all the points of P0. This gives us the plane

(𝑥,𝑦,𝑧)=𝐴+𝑠(5,2,−1)+𝑡(3,−2,4)

One of the things I've always liked about mathematics, especially at somewhat higher levels, is that it's not difficult to verify your work for yourself. What I said above was how you can do this.Can you check these for yourself? Does your plane contain the point A(2, 3, -1)? Since your plane is parallel to the given plane, it should contain the same two vectors as the given plane.

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