- #1

jsun2015

- 10

- 0

## Homework Statement

Using Washer Method: Revolve region R bounded by y=x^2 and y=x^.5 about y=-3

## Homework Equations

V= integral of A(x) from a to b with respect to a variable "x"

A(x)=pi*radius^2

## The Attempt at a Solution

pi(integral of (x^.5-3)^2 -(x^2)^2-3) from 0 to 1 with respect to x

The answer involves x^.5+3 instead of x^.5 -3. I don't understand why you would add instead of subtract 3; y decreased from 0 to -3 when revolved around y=-3