Calculus, Delta- Epsilon Proof Of Limits

[goofyfootsp]

Homework Statement

Is this the right direction to prove

Given that , prove that . Using the delta epsilon definition to prove that means that, for any arbitrary small there exists a where as:




If we choose any constant for (x) called C, as long as C does not equal zero, the equation follows:



whenever , since f(x) as x goes to a is equal to L.

Multiply the by the absolute vale of the constant C, , so you have



Now the product of absolute values is equal to the absolute value of the products so,

The Attempt at a Solution

 

[HallsofIvy]

There appear to be whole sections of your post missing!

 

[goofyfootsp]

calculations in attachment

I apologize but the attatchment has the work in it.