Calculus II - Series Comparison Test Problems

invasmani
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Homework Statement



I have two relatively similar problems:

1.) Sigma n=1 to infinity ((ln n)^3 / n^2)
2.) Sigma n=1 to infinity (1 / sqrt(n) * (ln n)^4)

I'm to prove their convergence or divergence using either the direct comparison test or the limit comparison test.

I understand both comparison tests, however, I am very much stumped on how to determine a working bn for the problems.

The Attempt at a Solution



I've tried using a known p-series, such as 1/(n^2) for problem #1, which is convergent. However, that p-series is not greater than the an in this case.

I'd appreciate any sort of direction on this.
 
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ln(n) grows more slowly than any power x^p for p>0. Can you suggest an interesting value of p that's relevant for 1) or 2)?
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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