Calulate the energy stored in capacitor

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The forum discussion focuses on calculating the energy stored in a capacitor arrangement with a potential difference of 100 V. The user calculated the net capacitance (Cnet) as 847 µF and determined the voltage across capacitors C1 (12.0 µF) and C2 (6.00 µF) to be 47.1 V. The energy stored in capacitor C1 was computed using the formula U = 0.5 x C x V², resulting in 0.013 J. However, the user questioned the correctness of their answer, prompting clarification on the calculation of Cnet, which involves recognizing that C1 and C2 are in parallel and their effective capacitance is in series with C3 (16.0 µF).

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a potential difference V = 100 V is applied across a capacitor arrangement with capacitances C1 = 12.0 µF, C2 = 6.00 µF, and C3 = 16.0 µF. Find the following values.

i calculated cnet and got 847e-6f
voltages across c1 and c2 i got 47.1

now i have to calulate the energy stored in capacitor 1

u = .5 x c x v^2
u = .5 x 12e-6 x 47.1^2 = 0.013J

but i am getting the answer is wrong can anyone confirm?
 

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How did you get cnet? C1 and C2 are in parallel, and effective capacitance of 1 and 2 is in series with C3.
 

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