Calulate the energy stored in capacitor

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The discussion focuses on calculating the energy stored in a capacitor arrangement with given capacitances and a potential difference. The user calculated the net capacitance as 847 µF and determined the voltage across capacitors C1 and C2 to be 47.1 V. However, the energy calculation for capacitor C1 using the formula U = 0.5 x C x V² yielded an incorrect result. Clarification is sought on the calculation of net capacitance, noting that C1 and C2 are in parallel while their effective capacitance is in series with C3. Accurate calculations are essential for determining the correct energy stored in the capacitor.
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a potential difference V = 100 V is applied across a capacitor arrangement with capacitances C1 = 12.0 µF, C2 = 6.00 µF, and C3 = 16.0 µF. Find the following values.

i calculated cnet and got 847e-6f
voltages across c1 and c2 i got 47.1

now i have to calulate the energy stored in capacitor 1

u = .5 x c x v^2
u = .5 x 12e-6 x 47.1^2 = 0.013J

but i am getting the answer is wrong can anyone confirm?
 

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How did you get cnet? C1 and C2 are in parallel, and effective capacitance of 1 and 2 is in series with C3.
 
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