Camera Flash Circuit Explanation

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Firefox123
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These two websites:

http://www.increa.com/reverse/dc/

and

http://thesignalpath.com/blogs/2011/06/12/camera-flash-circuit-and-nixie-tube-tutorial/

have very similar circuits for a standard camera flash circuit...and overall do a decent job explaining them.

There is one question I have though...one thing they do not explain in detail and I'm not quite sure what the answer is.

The question is WHY the transistor ever shuts off? WHY does it go into the cutoff mode for a short period of time? What is causing this?

So...what causes the transistor to go into cutoff? Does anyone have a good (detailed) explanation?

Thanks!
 
No takers yet ?

i think it has to do with inductance of the little transformer.
Recall current flowing in an inductance causes magnetic flux
but iron is non-linear it can only hold so much flux,
so at some amount of current an iron core inductor quits behaving like an inductor , its flux quits increasing with current...



from your first link (and credit to those folks at http://www.increa.com/reverse/dc/ )

Schematic of a Kodak disposable camera flash circuit: 1.5 V battery, 220 ohm resistor, transformer, D965 transistor, 1N4007 diode, 160 uF 330 V capacitor, 3.9 M and 1 M resistors, .002 u capacitor, flash tube, and flash switch.


when transistor conduction starts,
current begins to increase in the transformer primary increasing flux in its core
and voltage in every turn of every winding is in proportion to rate of flux increase

as he said, voltage in secondary during increasing flux interval turns transistor on more(note dots) and that's positive feedback

now here's the key to it -
when transformer core has all the flux it can handle
it "saturates" and flux stops increasing
so there's no more volts induced in any of the turns of either winding
so secondary winding no longer promotes primary current
and when primary current begins to drop,
flux starts to decrease,
reversing polarity of induced voltage in all windings
so secondary winding now turns the transistor off and there it stays until flux settles back near zero.

note his positive feedback operates in BOTH half cycles ! That's why it gives that snap-action full-on full-off cycling.

we are taught to usually think of transformers as processing sinewaves
but they are at heart just inductors.

old jim
 
Last edited:
jim hardy said:
No takers yet ?

i think it has to do with inductance of the little transformer.
Recall current flowing in an inductance causes magnetic flux
but iron is non-linear it can only hold so much flux,
so at some amount of current an iron core inductor quits behaving like an inductor , its flux quits increasing with current...



from your first link (and credit to those folks at http://www.increa.com/reverse/dc/ )

Schematic of a Kodak disposable camera flash circuit: 1.5 V battery, D965 transistor, 220 ohm resistor, 1N4007 diode, 160 u 330 V capacitor, 3.9 M and 1 M resistors, .002 u capacitor, flash xenon tube and a switch labelled flash.


when transistor conduction starts,
current begins to increase in the transformer primary increasing flux in its core
and voltage in every turn of every winding is in proportion to rate of flux increase

as he said, voltage in secondary during increasing flux interval turns transistor on more(note dots) and that's positive feedback

now here's the key to it -
when transformer core has all the flux it can handle
it "saturates" and flux stops increasing
so there's no more volts induced in any of the turns of either winding
so secondary winding no longer promotes primary current
and when primary current begins to drop,
flux starts to decrease,
reversing polarity of induced voltage in all windings
so secondary winding now turns the transistor off and there it stays until flux settles back near zero.

note his positive feedback operates in BOTH half cycles ! That's why it gives that snap-action full-on full-off cycling.

we are taught to usually think of transformers as processing sinewaves
but they are at heart just inductors.

old jim



Jim...thanks for the reply. I need to think about this more, but on a first look I think this might be what is happening.

Thanks again!
 
I need to think about this more, ...

indeed that's the thing to do.
You need to get to where you can work a machine in your head
and check the formulas that naturally fall out from your understanding against textbook formulas
when they converge you are probably right.

Observe that so long as flux is increasing, the induced voltage helps push current through the 220 ohm resistor.
When flux stops increasing due to saturation,
induced voltage drops off
reducing base drive
decreasing base current hence collector and primary current
which begins the 'decreasing flux' half cycle.

That works for me.

Now consider this drawing from another site
Schematic of the Fuji Flash Unit 1 circuit: 1.5V AA battery BT1, inverter transformer T1 with 6T and 15T windings, transistor Q1 2SD1960, resistor R1 220, charge switch S1, diode D1, capacitor C1 100uF 330V, resistors R2 4.7M and R3 10K, capacitor C2 .022uF, neon lamp IL1 NE2X Ready, trigger transformer T2, fire switch S2, and flashlamp FL1.


i think he has his 15 turn winding connected backward , 220 ohm should go to the tap not the end (or else he needs another dot on bottom of winding and reverse direction of those turns)

that had me stumped last night.
Somebody please correct me if I'm wrong ?

old jim
 
jim hardy said:
indeed that's the thing to do.
You need to get to where you can work a machine in your head
and check the formulas that naturally fall out from your understanding against textbook formulas
when they converge you are probably right.

In my short career...I have found that to usually be the case.

jim hardy said:
Observe that so long as flux is increasing, the induced voltage helps push current through the 220 ohm resistor.
When flux stops increasing due to saturation,
induced voltage drops off
reducing base drive
decreasing base current hence collector and primary current
which begins the 'decreasing flux' half cycle.

That works for me.

I think you are right...I also think this is why the OFF time of the transistor is so short compared to the ON time...the reverse EMF quickly dissipates and the process starts all over again...

jim hardy said:
Now consider this drawing from another site
Schematic of a Fuji Flash Unit 1 camera flash circuit: 1.5V AA battery BT1, transistor Q1 (2SD1960) driving inverter transformer T1, diode D1, 100uF 330V capacitor C1, 4.7M resistor R2, NE2X Ready neon lamp IL1, trigger transformer T2, and flashlamp FL1 with Fire switch S2.


i think he has his 15 turn winding connected backward , 220 ohm should go to the tap not the end (or else he needs another dot on bottom of winding and reverse direction of those turns)

that had me stumped last night.
Somebody please correct me if I'm wrong ?

old jim

That looks wrong to me also...
 
Okay I have been thinking about this a bit more...

And now I am thinking it is not due to the transformer saturating...

I think it is the transistor.

Once the transistor saturates we have maximum current flowing through it...so the current stops increasing and is constant...this causes the flux/induced voltage in the secondary to quickly drop to zero...and this is what causes the transistor to go into cut-off.

Of course the transistor goes into cut-off before "zero volts" is reached...

So I think it has more to do with the transistor saturating than the actual transformer itself...

Let me know what you think.