Can a Dam Turbine Meet a Paper Mill's Energy Needs?

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The paper mill requires 5000 kW to operate at full capacity and generates 14 tons of paper per hour, purchasing electricity at $0.10 per kW*hr. A dam with a height of 10 meters can supply water to a turbine, but only if the flow exceeds 50 cubic feet per second. The generator's efficiency is 75%, and the kinetic energy from the water can be calculated using the potential energy formula E = mgh. To determine the percentage of the mill's power requirement that the dam can supply, one must calculate the power output of the turbine based on the water flow and efficiency, then compare it to the mill's energy needs.
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a mill requires 5000kW to operate at full capacity, produces 14tons of paper per hour, purchases electricty for $.10/kW*hr

There is a dam 10m high that supplies water to a turbine. the river can be used only if the flow is above 50 cubic ft/sec. efficiency of generator is 75%

how am i supposed to find "What percentage of the mill's power requirement can the dam supply?" I'm so lost
 
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Each second, 50 ft^3 of water transfers its kinetic energy to the mill. This energy will be equal the water's potential energy at the top of dam. So E = m g h, where m is the mass of the water (mass = density * volume), and h is the height of the damn (let's assume the water comes out at the bottom). So the power is .75 * E per second. Divide this into how much power the mill needs to get the percentage.
 
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