I Can a State with Nonmeasurable Local Properties be Described by Quantum Rules?

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If the state considered is :##\frac{1}{\sqrt{2}}\left[\left(\begin{array}{c}1\\0\\0\end{array}\right)\left(\begin{array}{c}0\\1\end{array}\right)-\left(\begin{array}{c}1\\0 \end{array}\right)\left(\begin{array}{c}0\\0\\1\end{array}\right)\right]##

It seems to me it were not locally measurable since it is a mixture of spin 1 boson with a spin 1/2 ?

However how about considering as a global 6x1 vector and apply usual quantum rules, would it make any sense ?
 
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This notation is totally unknown to me. Could you explain, what you mean by your symbols?
 
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A citation of your source might help, too.
 
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Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!

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