Can a Thermosyphon Rankine Power Plant Produce 0.1-0.25 kW of Power?

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SUMMARY

The discussion focuses on the feasibility of generating power in the range of 0.1-0.25 kW using a thermosyphon Rankine power plant. The user is attempting to calculate the mass flow rate (m) necessary to achieve this power output, given that the system operates as an ideal Rankine cycle without work input at the pump stage. Key equations utilized include Qin/m = h1-h4 and Wcycle = m[(h1-h2)-(h4-h3)], which are essential for determining the net power output. The user seeks clarification on whether to derive the mass flow rate independently or if it can be calculated from existing parameters.

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Homework Statement



I am supposed to see if there is a feasibility of producing power in the 0.1-0.25 kW range. I am working with a thermosyphon Rankine power plant. It is an open ended design problem

My question is that I am getting hung up on finding the mass flow rate. My professor says to treat it as an ideal Rankine cycle, but there is no work input at the pump stage (virtual pump). I have calculated the systems at each spot, so I have all enthalpy values, all temp and pressure values and all entropy values at each station.


Homework Equations



Qin/m = h1-h4
Qout/m = h2-h3
Wp/m = h4-h3
Wt/m = h1-h2
Wcycle = m[(h1-h2)-(h4-h3)] = m[Wt/m-Wp/m]


The Attempt at a Solution



I have calculated Qin/m, and Qout/m. But I am confused as how to calculate Wcycle (net power). Because m is in the way, I cannot compare the value I get of Wcyc/m. So my question is, is m a value I need to compose on my own since it is open ended, or is there a way I am forgetting to calculate it? If I do need to make my own value, how do I come up with that value?
 
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You're correct in that you can only calculate Wcycle/m. If you have twice as much of the substance, the engine will do twice as much work.

So: what does m/t need to be, in order to generate 0.1 to 0.25 kW?
 

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