Can an Iron Ball Find Equilibrium in Deep Desert Sand?

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An iron ball placed in deep desert sand will sink until it reaches an equilibrium level where its density matches that of the surrounding sand. The discussion explores whether the sand can be treated as a fluid, with some arguing that it behaves similarly to a fluid due to the interactions between sand particles. However, others contend that the presence of air and water between sand grains complicates this model, suggesting that surface forces dominate rather than volume forces found in true fluids. The concept of liquefaction is also mentioned, indicating that under certain conditions, sand can behave like a fluid. Ultimately, the equilibrium level of the iron ball depends on the density characteristics of the sand and the forces at play.
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Let assume a desert with very deep sand
and an iron ball on the ground level.
Due to small perturbations (wind, small earthquakes, etc.)
the iron ball will sinking down.
Is there an equilibrium level,
or the iron ball will sink down to "negative infinity level"?
 
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The ball will (in an ideal system) sink to the point where it's density is equal to the density of the rock around it.
The density of the Earth's liquid outer Core is around 10-12 g/cc
Iron has a density of around 7.8 g/cc so will sink to this level
 
I don't know if you mean the sand is "deep" enough that you consider it infinite, since I can't imagine you are referring to the centre of the Earth when you say "negative infinity".The ball should fall until its density is equal to the density of the sand around it, as long as you treat the sand as a fluid. I don't know if an earthquake will move a grain of sand once it becomes so deep that there is 1 metric tonne of sand directly above it.
 
But it is not an ideal fluid.
 
No one said anything about an ideal fluid. For the purposes of this problem, sand can be considered as a fluid. Now, if you were to drop something in water, which is only very slightly compressible and so has the same density "all the way down", if you drop an object into water, one of three things can happen. If the density of the object is less than the density of water, it will float on top of the water. If the density of the object is greater than the density of water, it will sink to the bottom. If the density of the object is exactly the same as the density of water, it will float at a height determined by other things (the force with which it hit the water when it was dropped for example).

Now, if you are assuming that your "sand" always has the same density, then the object will sink all the way to the bottom of the sand (to the center of the Earth if the sand goes that far). If you are assuming that the "sand" increases in density as you go deeper, then the object will sink until the density of the "sand" around it is equal to its density as NobodySpecial said.
 
But it is not fluid.
And I think that density can change in homogeneous gravitational field.
 
maybe "granular fluid" but its only notation
 
We aren't saying sand is a fluid, we are describing it as one. The particles of sand react in a similar way to the molecules in a fluid.

You are just nit-picking over semantics.
 
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jarednjames said:
We aren't saying sand is a fluid, we are describing it as one. The particles of sand react in a similar way to the molecules in a fluid.

I don't think so. Between sand grain there is air and also water can enter into the material.
And also in fluids between molecules there are volume forces, but in sand there are only surface forces I think. Maybe fluid model is a good assumption, but in this situation when we want to study long time scale, i think its not enough.
 
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