Can Any Continuous Coordinate Transformation Be a Local Poincare Transformation?

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micomaco86572
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Can any continuous coordinate transformation on a differential manifold be viewed as a poincare transformation locally in every tangent space of this manifold?

Thx!
 
on Phys.org
yeah, I see. But if we exclude this scale transformation, can we still say the coordinate transformation could be viewed as the local poincare transformation?
 
arkajad said:
This is what you do in gauge theories of the Poincare group.

http://www.springerlink.com/content/qv46n02uq4301315/" by K. Pilch.

Yeah,so I am thinking about whether the local poincare transformation includes all the continuous coordinate transformations except the scale transformation mentioned above.
 
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micomaco86572 said:
Yeah,so I am thinking about whether the local poincare transformation includes all the continuous coordinate transformations except the scale transformation mentioned above.

No. The Poincare group isn't even well defined on a generic manifold (e.g., one that has the wrong number of dimensions).
 
Infinitesimally, we can expand a vector field (infinitesimal diffeomorphism) as:

[tex]\xi(x+h)^\mu =\xi^\mu (x)+a^\mu_\nu h^\nu +...[/tex]

To kill the unwanted degrees of freedom we impose the condition of "no scalings" which amounts to assuming that [tex]a^\mu_\nu[/tex] is a Lorentz matrix.
 
arkajad said:
Infinitesimally, we can expand a vector field (infinitesimal diffeomorphism) as:

[tex]\xi(x+h)^\mu =\xi^\mu (x)+a^\mu_\nu h^\nu +...[/tex]

To kill the unwanted degrees of freedom we impose the condition of "no scalings" which amounts to assuming that [tex]a^\mu_\nu[/tex] is a Lorentz matrix.

Are you claiming that this works on a one-dimensional manifold? If not, then what conditions do you propose adding in addition to the ones given by the OP?
 
bcrowell said:
Are you claiming that this works on a one-dimensional manifold?

First tell me your definition of a poincare transformation on a one-dimensional manifold. I am really curious!