Can Boolean Algebra Simplify Complex Expressions Using Postulates and Theorems?

AI Thread Summary
The discussion focuses on simplifying the Boolean expression F = xyz' + xy'z' + x'yz + xyz using postulates and theorems. The initial steps involve applying the distributive law and the complement law, leading to the expression F = x(yz' + y'z') + yz. The simplification process highlights the potential to factor out z' from the first term. Participants are seeking assistance in further simplifying the expression. The conversation emphasizes the application of Boolean algebra techniques to achieve a more concise form.
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1. Simplify the expression:

F = xyz' + xy'z' + x'yz + xyz2. Postulates and theorems

The Attempt at a Solution



F = xyz' + xy'z' + x'yz + xyz

= x(yz' + y'z') + yz(x' + x) (Distributive)

= x(yz' + y'z') + yz.1 (Complement)


= x(yz' + y'z') + yz (identity)

This is where I need help.
 
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Notice that you can factor the z' out of the first term.
 
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