Can Both Ligands in Ru(phen)2(NCS)2 Bind via the Same Atom?

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The discussion centers on the linkage isomerism of the complex Ru(phen)2(NCS)2, specifically whether both ligands can bind through the same atom. It is established that the NCS ligand can exhibit linkage isomerism, leading to configurations where the nitrogen or sulfur atoms are involved in bonding with the ruthenium center. The participants identify three distinct isomers: one with nitrogen linkage, one with sulfur linkage, and a mixture of both. There is also mention of a technically possible fourth isomer, but it is considered equivalent to one of the others. The conversation concludes with a consensus on the existence of three main isomers in this complex.
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[SOLVED] Linkage isomer in complexes

I would like to ask a question on linkage isomer on complexes.
Say, I have a complex Ru(phen)2(NCS)2.
NCS can exhibit linkage isomer.
Suppose I focus on linkage isomerism only, regardless of optical isomer or geometrical isomer.
Surely, the complex can exist as S-C=N->Ru<-N=C-S and N=C-S->Ru<-S-C=N.
Can the complex be exist as S-C=N->Ru<-S-C=N.

p.s.: sorry for my poor representation, = means triple bond and either -> or <- is dative covalent bond.

Thanks.
John
 
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Theres 3 isomers in that case isn't there?

1x N linkage
1x S linkage
1x Mixture

Theres technically four, but since the other "Mixture" isomer is equivalent to the first one chemically, I'd say there was three personally...
 
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