Can Fleeting Heavy Atoms Form Stable Molecules Before Decay?

  • Thread starter Thread starter JonW.24
  • Start date Start date
  • Tags Tags
    Atoms
JonW.24
Messages
6
Reaction score
0
I read about scientists creating new heavy elements such 117 and that the properties of such exotic elements are mostly unknown because the scientist have just microseconds before they decay. Would it be at all possible to bond some new molecule with the heavy atom and some other appropriate atom before it decayed? Is there a chance it would last long enough to study as a molecule?
 
Physics news on Phys.org
This is getting into the frankly incredible field of single-atom chemistry. If the dynamics of the molecule formation is shorter than the lifetime of the superheavy element, then sure, you can do it (and I'm no chemist, but I'm pretty sure the dynamics are short enough). I don't think it would be the near-term focus of single atom chemistry though - as you say, there is plenty of unknown chemical properties before we start thinking about how they play in molecules.

http://newscenter.lbl.gov/2014/05/20/superheavy-chemistry-one-atom-at-a-time/
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
Back
Top