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A sinusoidal EM wave which length l is very great, hits a photoelectric device.
According to HUP, a sinusoidal EM wave with finite length l has a spectrum of frequencies which broadness is inversely proportional to l. So, if l is very great, the energy uncertainty is very low, and this, still for HUP, should mean that the time required to make that energy measurement is high. Or not?
If this were true, why, instead,the photoelectrons are emitted almost instantly?
According to HUP, a sinusoidal EM wave with finite length l has a spectrum of frequencies which broadness is inversely proportional to l. So, if l is very great, the energy uncertainty is very low, and this, still for HUP, should mean that the time required to make that energy measurement is high. Or not?
If this were true, why, instead,the photoelectrons are emitted almost instantly?