Can I get Surface Density from Volume Density?

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To determine the surface density of a thin, circular aluminum membrane without a given thickness, one can use the volume density of aluminum. While some suggest approximating surface density as a function of thickness, others argue that this leads to contradictions regarding mass and density. A practical approach is to consider the thickness as the atomic radius of aluminum, allowing for a calculation of surface density based on this approximation. The discussion highlights the complexities in transitioning from volume to surface density, especially for circular membranes. Ultimately, the problem remains challenging and may require further exploration of the assumptions involved.
Farina
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I'm working on a vibration frequency problem
involving a thin, circular aluminum membrane
with a radius of 0.01m.

I know the volume density of Al.

How do I arrive at a surface density for this circular
membrane -- especially since I'm not given the
thickness (I'm told that frequencies for thin membranes
are independant of thickness).

I could see how to do this if I had a rectangular membrane,
but I have a circular membrane instead.

??
 
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Yes, you can calculate the surface density from the volume density. It's just \sigma = \rho ^ {2/3}
 
No, I don't think you can. If something has surface density \sigma, and you stack 3 thin sheets on top of each other, the total mass will be the mass of the three sheets. Now, something with finite thickness would be like having an infinite number of thin sheets stacked on top of each other, so the mass would be infinite (and so would the volume density).

Conversely, assume something has volume density \rho. Let's say that we take a very bad approximation of it's surface density by taking a 1cm thick piece of the substance, and approximating it's surface density to be it's mass/surface area = mass/(volume/1cm) = 1cm * \rho. Now, the "true" surface density would be this number as the thickness approches zero. If we start with a thickness t = 1cm, then we have that it's "bad-approximate" surface density is t\rho. What we need to do, obviously, is evaluate the limit as t approaches zero, and since \rho is just some positive finite number, the limit is zero, so it's surface density is zero, which is what we have in real life (because objects are 3-d).

I'm not sure how to go about solving your problem, but the best suggestion I can give is to treat "thin" as having the thickness of the atomic radius of aluminum. You can then treat the membrane as a zero-thickness membrane with surface density (approximated to) t\rho, where t is the radius of aluminum atom, and \rho is its density.

Gokul is saying something else, I'm not sure where he's getting that from.
 
I assume you mean a sperical membrane not circular -- the volume density then tells you the mass of the membrane -- thickness assumed at some value -- so you have the details the rest is up to you -- I would not know how to solve this offhand.
 
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