Can I Solve for A and B in These Equations?

  • Thread starter Thread starter clemon!!
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AI Thread Summary
The equations 80A = 12000 - AB and 2000A = 2000 - AB can be solved for A and B. To find A, subtract the first equation from the second, which simplifies the process. Once A is determined, it can be substituted back into either equation to find B. There are suggestions for using Excel to automate the calculations, but concerns about convergence of the equations are raised. Overall, the discussion emphasizes that A and B can be solved, and methods for doing so are provided.
clemon!!
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80A = 12000 - AB
2000A = 2000 - AB

I can find A and B right? If not I can provide more??


Thanks :o !
 
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Yes you can find out A and B !
 
also is there any way to set up excel so that as i change the figures the answer what A and B is automatically changes?

i'm sorry to be so bad at math - it's been like 12 years since i stuided any :o
 
lazyaditya said:
Yes you can find out A and B !

honestly - i am using software that runs out in like 20 hours. this is a music hobby thing - i don't suppose you can give me the answer plus also if excell will do it for me?? i know it'd be simple for everyone here... :) :) !there are online calculators but they don't seem to cope with the A*B component!
 
Hey clemon.

Minus the first equation from the second and collect the terms for the A's and solve for A. Then plug A into one of the equations and solve for B.
 
they don't converge!

what about:

100=A/(100-B)+C
12000=A/(80-B)+C
200=A(5000-B)+C
thanks!
 
thanks - I'm trying to find it with excel atm. not sure if these figures even converge tbh.
 
80A = 12000 - AB
2000A = 2000 - AB

Didn't you consider getting rid of the "AB" term by subtracting one equation from the other? 80A- 2000A= -1920A= 10000. Solve that for A and then solve either of the two equations, using that value of A, for B
 

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