Can I use only one substitution for integral?

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Homework Help Overview

The discussion revolves around the use of substitutions in the context of evaluating the integral \(\int \frac{dx}{\cos^2 x + 4\sin^2 x}\). The original poster explores the implications of making multiple substitutions in their solution process.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to clarify whether it is valid to make more than one substitution in their integral solution, given that the problem initially specifies a substitution. Some participants discuss the appropriateness of their approach and the implications of their substitutions.

Discussion Status

Participants have provided feedback on the original poster's approach, indicating that their method appears correct. There is a dialogue about the validity of making additional substitutions beyond the one specified, with differing opinions on whether this is acceptable in the context of the problem.

Contextual Notes

There is mention of a teacher's perspective that discourages substitutions beyond what is specified in the problem, which adds a layer of complexity to the discussion regarding acceptable methods in homework settings.

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Homework Statement



By using the substitution t = tan x, find

[tex]\int \frac{dx}{\cos^2 x+4\sin^2 x}[/tex]

Homework Equations


The Attempt at a Solution



Well let tan x=t

[tex]\frac{dt}{dx}=\sec^2 x=\tan^2 x+1=1+t^2[/tex]

the integral then becomes

[tex]\int \frac{dx}{\frac{1}{\sqrt{1+t^2}}^2+4\frac{t}{\sqrt{1+t^2}}^2}[/tex]

which simplifies to

[tex]\int \frac{1}{1+4t^2}[/tex]

Then from here i make another substitution **

let t= 1/2 tan b

dt/db = 1/2 sec^2 b

[tex]\int \frac{1}{1+4(\frac{1}{2} \tan b)^2} \cdot \frac{1}{2}\sec^2 b db[/tex]

= b + constant

Back substitute

= [tex]\frac{1}{2}\tan^{-1} (2t)[/tex] + constant

= [tex]\frac{1}{2}\tan^{-1}(2\tan x)[/tex] + constant

Am i correct? Especially this part ** where i made another substitution, is that valid? Or when the question specified the substitution, i have to stick that one substitution only?
 
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Looks okay to me.
If you remember that
[tex]\int \frac{dy}{1 + y^2} \, dy = \tan^{-1}(y)[/tex]
then [itex]y = 2t[/itex] immediately gives you
[tex] \int \frac{dt}{1+4t^2} = \frac{1}{2} \int \frac{dy}{1 + y^2} = \frac{1}{2} \tan^{-1}(y) = \frac{1}{2} \tan^{-1}(2 \tan x)[/tex]

(Note that if this was a definite integral, you would have to be very careful with the integration boundaries in these subsitutions)
 


CompuChip said:
Looks okay to me.
If you remember that
[tex]\int \frac{dy}{1 + y^2} \, dy = \tan^{-1}(y)[/tex]
then [itex]y = 2t[/itex] immediately gives you
[tex] \int \frac{dt}{1+4t^2} = \frac{1}{2} \int \frac{dy}{1 + y^2} = \frac{1}{2} \tan^{-1}(y) = \frac{1}{2} \tan^{-1}(2 \tan x)[/tex]

(Note that if this was a definite integral, you would have to be very careful with the integration boundaries in these subsitutions)

thanks Compuchip! So it's ok to make another substitution other than the one specified in the question? My teacher said otherwise, saying that it's not appropriate to make substitutions other than the one specified in the question. I want to get my facts right first before i get into another heated argument with her.

True, as for definite integrals, we will need to modify the limits in accordance with the substitution we make.
 


Personally, I think that if you can find a correct way to solve the question yourself (even if it is not exactly the way your teacher or anyone else has in mind) it is appropriate.

In this case, you could even argue that 2t -> t is not a full-fledged variable substitution but simply a rescaling, and the integral of 1/(1 + t²) is a standard integral which you can write down immediately whenever you encounter it (however you have proved that standard integral nicely here, which is not bad to do once in your life :) ).
 


CompuChip said:
Personally, I think that if you can find a correct way to solve the question yourself (even if it is not exactly the way your teacher or anyone else has in mind) it is appropriate.

In this case, you could even argue that 2t -> t is not a full-fledged variable substitution but simply a rescaling, and the integral of 1/(1 + t²) is a standard integral which you can write down immediately whenever you encounter it (however you have proved that standard integral nicely here, which is not bad to do once in your life :) ).

Thanks again, Compuchip.
 

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