Can l'Hospital's Rule be Used to Solve exp(i*k-a)*x=0 for x=inf?

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SUMMARY

The discussion centers on the application of l'Hospital's Rule to the equation exp(i*k-a)*x=0 as x approaches infinity. It is established that if the parameter 'a' is greater than zero, the limit approaches zero due to exponential damping, specifically in the form exp(-a*x)*f(x), where f(x) = exp(i*k*x) remains bounded. The conclusion is that l'Hospital's Rule can be effectively utilized in this scenario to evaluate the limit as x approaches infinity.

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teroenza
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Homework Statement


In a solutions manual I read exp(i*k-a)*x=0 when x= inf. I don't see how this happens.


Homework Equations





The Attempt at a Solution


Is there a procedure for dealing with this like l'Hospital's rule?
Like if I distribute the x for exp(i*k*x-a*x) then substitute inf, and get exp(inf-inf).
 
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teroenza said:

Homework Statement


In a solutions manual I read exp(i*k-a)*x=0 when x= inf. I don't see how this happens.


Homework Equations





The Attempt at a Solution


Is there a procedure for dealing with this like l'Hospital's rule?
Like if I distribute the x for exp(i*k*x-a*x) then substitute inf, and get exp(inf-inf).

Assuming throughout that k is real, the statement is true if a > 0, false if a ≤ 0. For the case a > 0 we just have "exponential damping" of the form exp(-a*x)*f(x), where f(x) = exp(i*k*x) remains bounded.

RGV
 
Yes, I'm sorry. a is positive and real. As is k
 

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