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Can someone check my work? (Finding a common divisor T)

  1. Apr 24, 2012 #1
    1. The problem statement, all variables and given/known data

    Look at my work in the picture.

    2. Relevant equations



    3. The attempt at a solution

    image 3.jpg


    I did a different method and I got 3 and 1 and still 1 is the only T that satisfies.
     
    Last edited: Apr 24, 2012
  2. jcsd
  3. Apr 24, 2012 #2

    Mark44

    Staff: Mentor

    Your photo is very difficult to read. Also, what is the statement you are trying to prove?
     
  4. Apr 24, 2012 #3
    I'm trying to find all values of natural numbers T that satisfy T l n^2-n+3 and T l n+1
     
  5. Apr 24, 2012 #4
    Take a look at this copy and the bottom is cut off. It is S={1}

    mathematics.jpg
     
  6. Apr 24, 2012 #5

    Mark44

    Staff: Mentor

    If n = 4, n + 1 = 5 and n^2 -n + 3 = 15, so 5 is in the set.
     
  7. Apr 24, 2012 #6
    Notice that I said "If n = 4".

    Here's your problem statement from post #3.
    There's no mention of "for every n."
     
    Last edited by a moderator: Apr 24, 2012
  8. Apr 24, 2012 #7
    Yes it divides it but not for every n.
     
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