# Can someone check my work? (Finding a common divisor T)

1. Apr 24, 2012

### mtayab1994

1. The problem statement, all variables and given/known data

Look at my work in the picture.

2. Relevant equations

3. The attempt at a solution

I did a different method and I got 3 and 1 and still 1 is the only T that satisfies.

Last edited: Apr 24, 2012
2. Apr 24, 2012

### Staff: Mentor

Your photo is very difficult to read. Also, what is the statement you are trying to prove?

3. Apr 24, 2012

### mtayab1994

I'm trying to find all values of natural numbers T that satisfy T l n^2-n+3 and T l n+1

4. Apr 24, 2012

### mtayab1994

Take a look at this copy and the bottom is cut off. It is S={1}

5. Apr 24, 2012

### Staff: Mentor

If n = 4, n + 1 = 5 and n^2 -n + 3 = 15, so 5 is in the set.

6. Apr 24, 2012

### mtayab1994

Notice that I said "If n = 4".

Here's your problem statement from post #3.
There's no mention of "for every n."

Last edited by a moderator: Apr 24, 2012
7. Apr 24, 2012

### mtayab1994

Yes it divides it but not for every n.