Can someone explain this time dilation problem to me?

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The discussion centers on the twin paradox in special relativity, where one twin travels to a star 10 light years away at 0.8c while the other remains on Earth. The traveling twin experiences time dilation, resulting in only 15 years passing for them compared to 25 years for the Earth-bound twin. The confusion arises from the fact that the traveling twin changes inertial frames when turning around, while the Earth twin remains in a single inertial frame throughout. This frame-switching is crucial to understanding the time difference experienced by each twin. Ultimately, the calculations confirm that the twin on the spaceship ages less due to the effects of special relativity.
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I'm going to use the time traveling twins example to try and explain the crossroads I'm at with special relativity. The one twin is back on Earth while the other twin is traveling to a star 10 light years away at .8c. We calculated how long it would take on the earth-star frame of reference, it would take approximately 12.5 years. However, it would ony take 7.5 years in the twin in the spaceship frame of reference due to length contraction. That's all well and good, I understand that. The end of the story is the one twin comes back and 25 years elapsed on Earth and only 15 years elapsed for the twin, the twin came back 10 years younger. I would like to know how come the twin on Earth isn't the twin who had only 15 years elapse. One could say that in the spaceships frame of reference that the Earth was moving away at .8c and not the ship. Someone explained it to me that it's because the ship turned around and wasnt in uniform motion anymore and whatnot but I just don't understand that. Any help will be appreciated.
 
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Try doing a search on "twin paradox" in this forum. Maybe one of the previous threads on this issue will help you. :smile:
 
This problem has been discussed ad nauseam at these boards, as you may well imagine.

Short answer is that the twin at Earth stays in the same inertial frame at all times, while the twin moving switches frames. If you were to calculate the proper time difference elapsed between the twins, you would get a compatible answer in all three frames. However, twin 2's spaceship is not a proper inertial frame, and that is where your logic goes wrong.
 
In an inertial frame of reference (IFR), there are two fixed points, A and B, which share an entangled state $$ \frac{1}{\sqrt{2}}(|0>_A|1>_B+|1>_A|0>_B) $$ At point A, a measurement is made. The state then collapses to $$ |a>_A|b>_B, \{a,b\}=\{0,1\} $$ We assume that A has the state ##|a>_A## and B has ##|b>_B## simultaneously, i.e., when their synchronized clocks both read time T However, in other inertial frames, due to the relativity of simultaneity, the moment when B has ##|b>_B##...

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