Can someone help me with calculating cartesian coordinates for a moving object?

AI Thread Summary
To calculate the Cartesian coordinates of an object moving from location L1 to L2 after traveling a distance D, first determine the distance d between L1 and L2 using the formula d = sqrt((x2-x1)² + (y2-y1)² + (z2-z1)²). The coordinates of any point along the line connecting L1 and L2 can be expressed as x = x1 + (x2-x1)(t/d), y = y1 + (y2-y1)(t/d), and z = z1 + (z2-z1)(t/d). By substituting t = D into these equations, you can find the coordinates of the object after it has traveled D units toward L2. This approach ensures accurate positioning in three-dimensional space. Understanding this formula is essential for solving similar problems in vector mathematics.
Ralgar
Messages
2
Reaction score
0
Hi. I was just wondering if anyone could help me with a formula to solve the following problem.

I have two locations (L1 and L2), which I know the cartesian coordinates of, situated in a three dimensional space. I also have a distance (D) which I also know the value of. D is not the distance between L1 and L2. If an object moves from it's starting location at L1 in a straight line towards L2, how do I calculate the cartesian coordinates of the object after it has traveled a distance of D units.

I'd certainly appreciate any assistance in this.

Cheers.
 
Mathematics news on Phys.org
Let L1= (x1,y1,z1) and
L2= (x2,y2,z2).

Let d= distance from L2 to L1= [sqrt]((x2-x1)2+(y2-y1)2+(z2-z1)2).

The any point on the line through L2 and L1 has coordinates
x= x1+ (x2-x1)(t/d)
y= y1+ (y2-y1(t/d)
z= z1+ (z2-z1)(t/d)

(notice that when t= 0, this is x= x1 and when t= d, this is x= x2, etc.)

In particular, taking t= D will give the coordinates of the point at distance D from L1 in the direction of L2.
 
Thank you.
 
Thread 'Video on imaginary numbers and some queries'
Hi, I was watching the following video. I found some points confusing. Could you please help me to understand the gaps? Thanks, in advance! Question 1: Around 4:22, the video says the following. So for those mathematicians, negative numbers didn't exist. You could subtract, that is find the difference between two positive quantities, but you couldn't have a negative answer or negative coefficients. Mathematicians were so averse to negative numbers that there was no single quadratic...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Thread 'Unit Circle Double Angle Derivations'
Here I made a terrible mistake of assuming this to be an equilateral triangle and set 2sinx=1 => x=pi/6. Although this did derive the double angle formulas it also led into a terrible mess trying to find all the combinations of sides. I must have been tired and just assumed 6x=180 and 2sinx=1. By that time, I was so mindset that I nearly scolded a person for even saying 90-x. I wonder if this is a case of biased observation that seeks to dis credit me like Jesus of Nazareth since in reality...
Back
Top