Can someone point me in the right directon

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Homework Help Overview

The problem involves integrating cot²x, with the original poster expressing difficulty in finding a suitable approach after attempting various substitutions and power reduction formulas.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • The original poster has tried substitutions and power reduction formulas but has not found success. Another participant suggests using the identity 1 + cot²(x) = csc²(x) to simplify the integration process.

Discussion Status

Some participants have provided guidance regarding trigonometric identities that may assist in the integration. The original poster acknowledges the usefulness of the suggested identity, indicating a positive direction in the discussion.

Contextual Notes

The original poster mentions spending considerable time on the problem, indicating a potential constraint in their understanding of trigonometric identities and integration techniques.

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the problem is to intigrate cot[tex]^{2}[/tex]x

now i kow that cot[tex]^{2}[/tex]x = [tex]\frac{cos^{2}x}{sin^{2}x}[/tex]

now iv tryed various substitutions like usig the power reducton forumulas...
and then using double angle substiutions but nothin seems to work for me

so i was wondering if someone could just tell me where to start so i can
finish this question... been trying to figure this out for like a hour now

thanks in advance
 
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Use the identities 1+ cot2(x)= csc2(x) so that cot2(x)= csc2(x)- 1. Since you know that the derivative of cot(x) is csc2(x), that should be easy.
 
Wow that was suprisingly simple thank a lot yea i didnt know about that identity that was the first time iv used it. Thnx a lot great help
 
There are many pages that list trig identities. Whenever I work with trig functions I always just open a page and have a look at how the functions in the question are related. There are loads of pages, but I do like wikipedias as it has a list of the 6 trig functions in terms of the others which is very handy for some integration questions when trig substitution is needed.

http://en.wikipedia.org/wiki/Trigonometric_identity
 
Wow very nice I am going to bookmark this page right away thnx again!
 

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