Can substitution help solve this improper integral?

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regnar
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I've been stuck on this problem for quite some time and I get as far as setting up the problem. They are asking me to evaluate this integral:

[tex]\int_0^1{\frac{(6ln4x)}{\sqrt{x}}dx[/tex] and I get as far as:

[tex]\lim_{b \to 0^+}{6\int_b^1{\frac{(ln4x)}{\sqrt{x}}[/tex]
 
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Substituting x = t^2 seems to work...
 
I'm not sure what you mean or where [tex]t^2[/tex] came from.
 
It's called substitution.

The substitution is [tex]t=\sqrt{x}[/tex] or [tex]t^2 = x[/tex]