Can the Inverse Hyperbolic Substitution Solve this Tricky Integral?

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Homework Help Overview

The discussion revolves around evaluating the integral of the expression (x + ln(x + sqrt(x^2 - 1)))^3 / (sqrt(x^2 - 1)), with participants exploring the potential of inverse hyperbolic substitution as a method for solving it.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants have attempted various methods to tackle the integral but have expressed difficulty in making progress. Some have suggested using computational tools like Wolfram Alpha and Maple, while others have proposed specific substitutions, such as x = cosh(y), to simplify the expression.

Discussion Status

There is ongoing exploration of different approaches, with some participants noting that certain substitutions appear to be effective. However, there is no explicit consensus on a single method or solution, and the discussion remains open to further contributions.

Contextual Notes

Participants have mentioned challenges in obtaining step-by-step results from computational tools and have questioned the clarity of their attempts to derive the integral. The nature of the integral and its relation to inverse hyperbolic functions is also under consideration.

AKJ1
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Homework Statement



(x+ln(x+sqrt(x^2-1)))^3 / (sqrt(x^2-1))

The Attempt at a Solution



I have tried so many different things with this integral but cannot seem to get anywhere with it. Its almost so nicely an inverse coshx but not quite.

Any help?
 
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Have you tried MMa or Wolfram Alpha?
 
AKJ1 said:

Homework Statement



(x+ln(x+sqrt(x^2-1)))^3 / (sqrt(x^2-1))

The Attempt at a Solution



I have tried so many different things with this integral but cannot seem to get anywhere with it. Its almost so nicely an inverse coshx but not quite.

Any help?

Have you tried Maple?
 
I have tried putting it in various forms into wolfram but returned nothing for step by step results. I tried taking the derivative of the said solution, but couldn't make any sense of it.
 
Try the substitution x=cosh(y).
 
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ehild said:
Try the substitution x=cosh(y).
Thank you! This worked out quite nicely!

:smile:
 
It makes sense that ehild's suggested substitution worked.

After all: ##\ \text{arcosh} (x) = \ln \left(x + \sqrt{x^{2} - 1} \right); x \ge 1 \ ##
 
SammyS said:
It makes sense that ehild's suggested substitution worked.

After all: ##\ \text{arcosh} (x) = \ln \left(x + \sqrt{x^{2} - 1} \right); x \ge 1 \ ##

and AKJ1 has noticed it...
 

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