Can the Parabolic Cylinder Function Solve a 2nd Order D.E. with a Constant?

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Homework Statement



\frac{d^2\phi(\eta)}{d\eta^2} = (\eta^2 - K) \phi(\eta)

Where K is essentially a constant, K = 2n + 1 (n is an integer).


The Attempt at a Solution



I don't even know where to begin since \phi is a function of \eta. A push in the right direction would be much appreciated.
 
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Stuff that looks like that usually wind up having solutions that are special functions (like Bessel etc). That appears to be a parabolic cylinder function. I got that by creative googling. It may have a simpler form for the case K = 2n + 1. Don't know. But that will give you a start for researching it. What kind of course is this? Are you supposed to be able solve it simply?
 
Thanks for the reply. This is for my quantum mechanics course, and the equation I set up relates to solving the time-independent Schrodinger equation for the harmonic oscillator in momentum-space. My textbook solved a similar DE using Hermite polynomials, but I was hoping there was a simpler solution. I'll search for special functions & "parabolic cylinder function." Thanks again for the reply.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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