Can Two Repelling Spheres Be Solved?

  • Thread starter Thread starter duhduhduh
  • Start date Start date
  • Tags Tags
    Spheres
AI Thread Summary
Electrostatic forces adhere to Newton's third law, meaning if charge Q exerts a force of 2.0 N on charge q, then q exerts an equal force of 2.0 N on Q. The discussion raises questions about the relationship between charge magnitudes and the forces they exert, suggesting that the charges can vary while maintaining constant force. A participant points out a potential error regarding the angle of a hanging charge, indicating that the mass must be greater for the force to remain balanced. The conversation concludes with a reminder about forum rules regarding post deletions after receiving assistance. Understanding the principles of electrostatics is essential for accurate problem-solving in this context.
duhduhduh
Messages
16
Reaction score
0
Solved.
 
Last edited:
Physics news on Phys.org
Electrostatic forces obey Newton's third law. Based on this, fill in the blank:

Suppose Q = 2q. If Q exerts an electrical force of 2.0 N on q, then q exerts an electrical force of ______ N on Q.
 
2q because the forces must be equal. Doesn't this agree with my answers?

Or does it mean that the charges can be anything as long as the force remains constant, in which case the answers would be:

True
False
True
True
True
 
One of your answers is still wrong. Hint: If the electrical forces are equal, then how can X hang at the smaller angle?
 
It must have a greater mass, so the mass one is false.

Thank you so much!
 
duhduhduh said:
Solved.

It is against the PF rules to deleted your posts after you have received help. Check your PMs.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top