Can Visible Photons Occur From -60.0 eV Electron Transitions?

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AI Thread Summary
Photons emitted from electron transitions in an atom with an energy level of -60.0 eV cannot be visible to the human eye, as their energy must fall between 1.8 eV and 3.1 eV. The relevant equations indicate that the energy difference between levels must be calculated, and for transitions from higher to lower energy states, the resulting photon energy will not reach the visible spectrum. The calculations suggest that the energy levels involved do not yield a transition energy that meets the visibility criteria. Therefore, the conclusion is that no visible photons can be produced from these transitions. Understanding the energy constraints is crucial in determining photon visibility.
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Homework Statement


Photons can be observed by the human eye as long as their energies are between 1.8 eV and 3.1 eV. In a particular atom one of the electron energy levels is at -60.0 eV. Can electron transitions, associated with this energy level produce photons that are visible to the human eye? Explain why your answer is ’yes’ or ’no’.

Homework Equations


I'm not sure about these

En=-(Z2E0)/n2

Em=-(Z2E0)/m2

n>m

The Attempt at a Solution


ΔEn→m=-Z2E0(1/n2-1/m2)

Where E0=13.6eV

I know the answer is 'no' and that we are meant to get to a point where n/m<1 to show that the answer is 'no', but I don't know where to go from here.
 
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The photons are produced when the electrons move over from a higher energy level to a lower energy level.
 
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