Can you clarify this step (charge density and integrals).

  • #1
Hi, if you have the book: Physics for Scientists and Engineers 8E, Serway Jewett

On page 675 (Chapter 23), Example 23.8 there is a step taken during the integration I don't understand:

How do you go from "2r dr" in the numerator to d(r^2)? If there is info or link to the property of integrals which explains this, I would appreciate seeing it. Thank you.
 

Answers and Replies

  • #2
1,065
54
hhhmmm...well, what do you get when you take the derivative or r2 ? In other words, what's d(r2)? is it 2rdr?
 
  • #3
1,225
75
Hi.

d(r^2)/dr = 2r is fundamental formula of derivative.

multiplying dr on both sides,

d(r^2) = 2r dr

Regards
 

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