Can you prove a differential equation has no analytical solution?

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SUMMARY

The discussion centers on proving that certain differential equations lack analytical solutions. A specific example provided is the equation y' = 2|x|, which has a general solution that is not analytic due to non-differentiability at x = 0. The conversation highlights the distinction between "analytical solutions" and "closed-form expressions," emphasizing that the latter can be determined through Differential Galois Theory. This area of study, rooted in Liouville's work, investigates the conditions under which a differential equation has a closed-form solution.

PREREQUISITES
  • Understanding of differential equations, particularly first and second order
  • Familiarity with concepts of analytic functions and closed-form expressions
  • Knowledge of Differential Galois Theory and its applications
  • Basic principles of calculus, including integration and differentiation
NEXT STEPS
  • Study Differential Galois Theory and its implications for closed-form solutions
  • Explore the properties of analytic functions and their power series expansions
  • Investigate specific examples of differential equations without analytical solutions
  • Learn about the relationship between continuity and differentiability in functions
USEFUL FOR

Mathematicians, students of advanced calculus, and researchers interested in the solvability of differential equations and the nature of analytical solutions.

chener
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Can you prove a differential equation has no analytical solution?

Teach me ,please!

Thank you a lot!
 
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Is the problem only to find one differential equation which has no analytical solution? If so, it is easy:

Take for example ##y'=2|x|##. This has the general solution ##y=sgn(x) x^2 + C##. None of these solutions is analytic, since they are not twice differentiable at 0.
 
But any such differential equation will have a solution that is analytic on some set. Chener, please give us more information on exactly what you mean.
 
HallsofIvy said:
But any such differential equation will have a solution that is analytic on some set. Chener, please give us more information on exactly what you mean.
Not if we take ##y'=f(x)##, where ##f(x)## is a function which is continuous everywhere but differentiable nowhere. The general solution of this equation is ##y=F(x)+C##, where ##F## is an antiderivative of ##f##. All these solutions are analytic nowhere, since they are twice differentiable nowhere.

But I agree that Chener must tell us exactly what he means.
 
Sorry my English is poor !
Let me think about how to express
 
Given a Differential Equation.

Is there Analytic Solutions or not?

And how do we know that?example: Given the equation y''=-y-y'+(1+|y|)*sin(t)

,how to prove a it has no analytical solution?Teach me ,please!

Thank you a lot!
Analytic Solution is resovle from Analytic Method.
 
Yes ,this is my mean! thanks!
 
chener said:
analytical solution!

You must explain what you mean by "analytical solution".

The term "analytic function" has a technical meaning from the theory of complex variables. It is a function that can be expanded in a power series.

You might be using the phrase "analytical solution" to mean a function that can be written down as a finite string of symbols - such as a finite sum of products of polynomials, trig functions etc. The phrase "closed form expression" is used to describe such a function.

Whether the solution to a problem in calculus has a solution that is a "closed form expression" is a question about how strings of symbols can be manipulated.

Whether the solution to a problem in calculus is an "analytic function" is a problem of \epsilon and \delta reasoning.
 
  • #10
Your question, now that it has been clarified to mean "Is there a method or theorem that can definitively tell whether a given differential equation has a closed-form expression in terms of some collection of elementary functions?" is the subject of Differential Galois Theory. This theory started out with Liouville's ideas on being able to tell when an integral had a closed form expression and has since expanded from there. It is still an active area of research, as far as I know. Here is a taste of how the theory proceeds, starting with the simplest task of a separable differential equation, which is just an integral: http://www2.maths.ox.ac.uk/cmi/library/academy/LectureNotes05/Conrad.pdf .
 

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