Can You Solve This Challenging Related Rates Problem?

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    Hard Related rates
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Homework Help Overview

The discussion revolves around a related rates problem, with participants sharing their approaches and insights regarding the calculations involved.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Some participants express uncertainty about their understanding and seek verification of their work. Others provide feedback on specific aspects of the calculations, such as the use of radians versus degrees and the value of sec²Θ derived from a diagram.

Discussion Status

The discussion includes various perspectives on the problem-solving process, with some participants offering constructive feedback and suggestions for improvement. There is an acknowledgment of the correctness of the work, but also an emphasis on the learning potential for others.

Contextual Notes

One participant notes the importance of not editing original posts to preserve the learning context for future readers. There is also mention of previous homework constraints that may have influenced the use of degree mode in calculations.

bobraymund
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Problem solved :)
 
Last edited:
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Looks good.
 
Really?? Haha, I had no idea what I was doing, honestly. If someone could double check my work, that'd be awesome. I know this is asking a lot. :p
 
I worked it out myself. Everything is correct. I would add a couple of notes about part c: You might want to switch your calculator to radian mode if you used a calculator to find arctan (5/12) just to be on the safe side. IMHO, there is never really any reason to choose to work in degree mode unless a problem is written that way or the answer needs to be in degrees. Also, it seems like you used the diagram to obtain the exact value of sec2 \Theta. That was a good choice (better than using any decimal approximation you obtained earlier). Also, not that it matters, but you could express 1/sec2 \Theta as cos2 \Theta if it would make it simpler for you to work with.

Everything was correct, but I wanted you to be able to see these things. Good Job.
 
Thanks Bear B for the input. Yeah, I caught myself doing it in DEG, because I was previously using it for my physics homework.

That is interesting that you point out I could have used the diagram to find the value of sec^2... I didn't do that, but just did right now and obtained the same answer. Thanks for pointing that out though, very interesting.

Thanks everyone. :)
 
In the future I recommend not editing your original post so that the problem disappears. While you are done being helped, there's some chance that someone else might be able to learn something from the discussion of your problem.
 

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