- #1

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Thanks

Richard.

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- Thread starter richardstan
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- #1

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Thanks

Richard.

- #2

Defennder

Homework Helper

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Yes, reactance behaves just like resistance in resistive circuits.

- #3

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Ummm, they add like this 5 & 4 = 1.

Capactitive reactance is 180 degrees out of phase from inductive reactance, so you actually subtract one from the another.

It's good to go back to the definitions. In series,

[tex]Z= i\omega L + \frac{1}{i\omega C}[/tex]

where [tex]X_{L}=Im(Z)[/tex]

Capactitive reactance is 180 degrees out of phase from inductive reactance, so you actually subtract one from the another.

It's good to go back to the definitions. In series,

[tex]Z= i\omega L + \frac{1}{i\omega C}[/tex]

where [tex]X_{L}=Im(Z)[/tex]

Last edited:

- #4

Defennder

Homework Helper

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- #5

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KW: 2.65 Amps:22 KVA: 2.65 Phase:1

voltage: 120 RPM:3600

HZ: 60

would appriciate anyons help!

russhart70

or give me a formula,? PLZ.

- #6

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[tex] = i\omega L - \frac{i}{\omega C} [/tex][tex]Z= i\omega L + \frac{1}{i\omega C} [/tex]

because: 1/i = -i

So, they subtract.

- #7

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- #8

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goin to get my books out real quick!

- #9

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do not understand wat L = wat I know is P=wats I = amps E=volts R=omes

- #10

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I guess I AM

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